(x^3+2x^2+5x)-(3x^2-x-7)=0

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Solution for (x^3+2x^2+5x)-(3x^2-x-7)=0 equation: 


Simplifying
(x3 + 2x2 + 5x) + -1(3x2 + -1x + -7) = 0

Reorder the terms:
(5x + 2x2 + x3) + -1(3x2 + -1x + -7) = 0

Remove parenthesis around (5x + 2x2 + x3)
5x + 2x2 + x3 + -1(3x2 + -1x + -7) = 0

Reorder the terms:
5x + 2x2 + x3 + -1(-7 + -1x + 3x2) = 0
5x + 2x2 + x3 + (-7 * -1 + -1x * -1 + 3x2 * -1) = 0
5x + 2x2 + x3 + (7 + 1x + -3x2) = 0

Reorder the terms:
7 + 5x + 1x + 2x2 + -3x2 + x3 = 0

Combine like terms: 5x + 1x = 6x
7 + 6x + 2x2 + -3x2 + x3 = 0

Combine like terms: 2x2 + -3x2 = -1x2
7 + 6x + -1x2 + x3 = 0

Solving
7 + 6x + -1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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